SOLUTION: how to solve log3(x)−6logx(3)=5

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Question 978281: how to solve log3(x)−6logx(3)=5
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
log3(x) - 6logx(3)=5
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Do you mean
log%283%2Cx%29+-+6log%28x%2C3%29=5
log(x)/log(3) - 6log(3)/log(x) = 5
log(x)*log(x) - 6*log(3)*log(3) = 5*log(3)*log(x)
log(x)*log(x) - 5*log(3)*log(x) - 6*log(3)*log(3) = 0
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Sub u for log(x)
u%5E2+-+log%28243%29%2Au+-+6log%283%29%2Alog%283%29+=+0
u+=+log%28243%29%2F2+%2B+sqrt%28%28log%28243%29%29%5E2+%2B+24log%283%29log%283%29%29%2F2
u =~ 2.05553 = log(x)
x =~ 113.63985
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u+=+log%28243%29%2F2+-+sqrt%28%28log%28243%29%29%5E2+%2B+24log%283%29log%283%29%29%2F2
u =~ -1.284318 = log(x)
x =~ 0.0519615