SOLUTION: 1/2=e^5700k Then you take LN of both sides LN(1/2)=LN(e^5700k) LN(1/2)=5700k Now solve for k Help Solving for k LN(1/2)=5700K

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 1/2=e^5700k Then you take LN of both sides LN(1/2)=LN(e^5700k) LN(1/2)=5700k Now solve for k Help Solving for k LN(1/2)=5700K      Log On


   

Question 977796: 1/2=e^5700k
Then you take LN of both sides
LN(1/2)=LN(e^5700k)
LN(1/2)=5700k
Now solve for k
Help Solving for k
LN(1/2)=5700K
Found 2 solutions by Boreal, jim_thompson5910:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
ln(1/2)=ln1-ln2=0-0.693
-0.693=5700k
k= - 0/693/5700= -0.0001216

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Use a calculator to get ln(1/2) = -0.693147

So ln(1/2) = 5700k turns into -0.693147 = 5700k

Divide both sides by 5700 to isolate k

k = -0.693147/5700 = -0.000122