SOLUTION: 19.) Solve for x algebraically. ln(2x+3)-ln(x-5)= 2 Here's what i have started. ln(2x+3)/(x-5)=2 I'm not sure where to go past here.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 19.) Solve for x algebraically. ln(2x+3)-ln(x-5)= 2 Here's what i have started. ln(2x+3)/(x-5)=2 I'm not sure where to go past here.      Log On


   

Question 772608: 19.) Solve for x algebraically.
ln(2x+3)-ln(x-5)= 2
Here's what i have started.
ln(2x+3)/(x-5)=2
I'm not sure where to go past here.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x algebraically.
ln(2x+3)-ln(x-5)= 2
Here's what i have started.
ln(2x+3)/(x-5)=2
I'm not sure where to go past here.
----------------
ln%28%282x%2B3%29%2F%28x-5%29%29=2+ Make it clear that it's the ln of the quotient.
%282x%2B3%29%2F%28x-5%29+=+e%5E2+
e^2 is a constant. Can you finish it?