SOLUTION: The problem is: 4^2x-7=64 I did 2x -7 * log 4 = log 64 then i did 2x-7 * .602 = 1.806 I'm not sure where to go from here.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The problem is: 4^2x-7=64 I did 2x -7 * log 4 = log 64 then i did 2x-7 * .602 = 1.806 I'm not sure where to go from here.      Log On


   

Question 108657: The problem is:
4^2x-7=64
I did 2x -7 * log 4 = log 64
then i did 2x-7 * .602 = 1.806
I'm not sure where to go from here.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
good so far ... dividing by .602 gives 2x-7=3