SOLUTION: How do u find the exact value for x that satisy the equation {{{x-ex^-1 = e(x-ex^-1)}}}

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Question 107431: How do u find the exact value for x
that satisy the equation
x-ex%5E-1+=+e%28x-ex%5E-1%29
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
x-ex%5E-1+=+e%28x-ex%5E-1%29
Let a=(x-ex^-1)
a=ea
a=0
x-ex^-1=0
x-e/x=0
-x+e/x=0
e/x=x
e=x^2
x=+-sqrt(e)
Ed