SOLUTION: Clara and her friends are planning a trip to a painball park. Find the cost of lunch and the cost of each paintball. What would be the cost for 400 paintballs and lunch? $25.00 f

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: Clara and her friends are planning a trip to a painball park. Find the cost of lunch and the cost of each paintball. What would be the cost for 400 paintballs and lunch? $25.00 f      Log On

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Question 950216: Clara and her friends are planning a trip to a painball park. Find the cost of lunch and the cost of each paintball. What would be the cost for 400 paintballs and lunch?
$25.00 for 500 paintballs
$15.00 for 200 paintballs
Lunch is included
Thank you very much.

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
x=price per paint ball
$25-500x=$15-200x Add 500x to each side.
$25=$15+300x Subtract $15 from each side.
$10=300x Divide each side by 300
$10/300=x
$0.0333=x ANSWER 1: Each paint ball costs $0.0333
$25-500x=lunch
$25-$16.65=lunch
$8.35=lunch ANSWER 2: Lunch costs $8.35
400($0.0333)+$8.35=lunch and 400 paintballs
$13.32+$8.35=lunch and 400 paintballs
$21.67=lunch and 400 paintballs
CHECK
$15-200(0.0333)=$8.35
$8.34=$8.35