SOLUTION: A cash drawer contains only fives and twenties. There are 8 more fives than twenties. The total value of money is $215. How many of each type of bill are there?

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Question 1096484: A cash drawer contains only fives and twenties. There are 8 more fives than twenties. The total value of money is $215. How many of each type of bill are there?
Found 2 solutions by josgarithmetic, sandeepvijay:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
f and t;
system%28f-t=8%2C5f%2B20t=215%29

f%2B4t=43
-
5t=35
t=7
-
f=15


15 Fives and 7 Twenties

Answer by sandeepvijay(8) About Me  (Show Source):
You can put this solution on YOUR website!
Let the number of $20 bills be x, then the number of $5 bills is x+8
Since, all the bills adds up to $215, 20%2Ax%2B5%2A%28x%2B8%29+=+215
Solving the above equation, we get x = 7
Therefore, Number of $20 bills = x = 7 and Number of $5 bills = x+8 = 15