Question 950603: Write the equation of a line perpendicular to the given line but passing through the given point.
y=2x-1 passing through the ordered pair (2, -2)
This is what I came up with
Again I will use the point slope form
y-y1= m(x-x1) and the point (2, -2)
First substitute the slope and my ordered pair
y-(-2)= -1/2 (x-2)
Becomes
y + 2= -x/2 + 2/2
Add -2 to both sides of the equation
y= -1/2x -1 which is the equation for the perpendicular line
This line will rise as you move left to right on the graph. The y-intercept is 1 above the origin and the x-intercept is 2 to the left of the origin.
Thank you
Answer by macston(5194)   (Show Source):
You can put this solution on YOUR website! You have some details wrong, like y-intercept, but your equation is correct.
y=2x-1 passing through the ordered pair (2, -2)
The slope of the perpendicular line is the negative reciprocal, so m=-1/2, x=2, y=-2
Using slope-intercept form to check:
y=mx+b
-2=-(1/2)2+b
-2=-1 +b
-1=b
Final equation:y=-(1/2)x-1
Slope is -1/2, negative slope drops from left to right.
Y-intercept is b, so y=intercept at (0,-1), one unit below the origin.
X-intercept is at (-2,0)
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