SOLUTION: I hit a block learning from a prep book. I can't seem to find the right order of operation. Is there anyway the following problems could be explained to me?
2x +3 (4x +5)= 1
Algebra ->
Equations
-> SOLUTION: I hit a block learning from a prep book. I can't seem to find the right order of operation. Is there anyway the following problems could be explained to me?
2x +3 (4x +5)= 1
Log On
Question 747493: I hit a block learning from a prep book. I can't seem to find the right order of operation. Is there anyway the following problems could be explained to me?
2x +3 (4x +5)= 1
You can put this solution on YOUR website! Consider the order of operations
1) parenthesis indicate "do me first"
2) execute division and multiplication from left to right, then addition and subtraction from left to right
your problem asks
2x +3 (4x +5)= 1
x-5= 4x+19
4x-5= 2x +17
-4x+8= 2x-16
16+2x =4x-8
1) 2x +3 (4x +5)= 1
2x +12x+15=1 here we multiply (4x+5) by 3
14x = -14 subtract 15 from both sides of =, combine like terms
x = -1 divide both sides of = by 14
2) x-5= 4x+19
-3x = 24
x = -8
3) 4x-5= 2x +17
2x=22
x=11
4) -4x+8= 2x-16
-6x= -24
x=4
5) 16+2x =4x-8
-2x=-24
x=12
