SOLUTION: solve the following algebraically: {{{2/(x-3)+4=2/(x-3)}}} I see that both sides of the equation have a {{{2/(x-3)}}} the only exception is the +4. I'm not sure what I am suppo

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Question 697090: solve the following algebraically:

I see that both sides of the equation have a the only exception is the +4. I'm not sure what I am supposed to do with the four. Should I put a one under it? I don't understand how I am supposed to solve for "x"
Found 2 solutions by ankor@dixie-net.com, MathLover1:
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
solve the following algebraically:

Actually there is no solution, but plunging ahead anyway
:
multiply thru by (x-3) and you have
2 + 4(x-3) = 2
Subtract 2 from both side
4(x - 3) = 0
4x - 12 = 0
4x = 12
x = 12/4
x = 3
:
Now you can see if you replace x with 3, in the original equation we have division by 0, hence no solution

Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!
...as you can see you have on both sides; it will be same number for any except because will make denominator equal to zero and divide by zero doesn't make sense
since you have only on left side, we can tell that , and there is no solution for that will make it equal