SOLUTION: A projectile is shot up from a below-ground trench, so that its position relative to ground level at t seconds is
y=f(t)=-11+120t-16t^2 feet
a) find the position of the proje
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-> SOLUTION: A projectile is shot up from a below-ground trench, so that its position relative to ground level at t seconds is
y=f(t)=-11+120t-16t^2 feet
a) find the position of the proje
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Question 421882: A projectile is shot up from a below-ground trench, so that its position relative to ground level at t seconds is
y=f(t)=-11+120t-16t^2 feet
a) find the position of the projectile relative to ground level at t=0.
b) sketch graph of f(t). give coordinates of the highest point, and all intercepts.
c)what is the highest position of the projectile?
d) Does the projectile ever reach 189 feet above ground level? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A projectile is shot up from a below-ground trench, so that its position
relative to ground level at t seconds is y=f(t)=-11+120t-16t^2 feet
:
a) find the position of the projectile relative to ground level at t=0.
t=0
f(0) = -11 + 120(0) - 16(0^2)
f(0 = -11, (11 ft below ground level at t=0)
:
b) sketch graph of f(t). give coordinates of the highest point, and all intercepts.
enter: y = -16x^2+120x-11, on your graphing calc, results:
c)what is the highest position of the projectile?
d) Does the projectile ever reach 189 feet above ground level?
