SOLUTION: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $1
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Question 34378: Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8, the value of the coins would be $10.45. How many dimes does he have? Answer by Paul(988) (Show Source):
You can put this solution on YOUR website! Dime value x 100 = 10
Nickel value x 100 = 5
Total value x100 = 565 and 1045
First equation:
Let the nickels be x
Let the dimes be y:
5x+10y=565
10y=565-5x
y=56.5-0.5x (subsitution)
Second EQUATION:
Dimes doubled --->2(10y)
Nickels increased by 8---> 5(x+8)
20y+5x+40=1045
Subsitute for y:
20(56.5-0.5x)+5x=1005
1130-10x+5x=1005
-5x=-125
x=25
y=56.5-0.5(25)
y=44
Hence, there are 25 nickels and 44 dimes.
PAul.
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