Question 280547: Solve 25x^2 + 49 = 0
This is what I have:
25x^2 + 49 - 49 = 0 + -49
25x^2 = -49
25x^2/25 = -49/25
x^2 = -1.96
x^2 + 1.96 = 1.96 + - 1.96
x^2 + 1.96 = 0
Therefore a solution cannot be determine. Am I correct or is the solution x^2 + 1.96 = 0? Found 2 solutions by Alan3354, Earlsdon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! 1.96 = 1.4^2
x^2 = -1.96 (a few steps back)
x = ± 1.4i
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There are no solutions using real numbers.
i = sqrt(-1)
You can put this solution on YOUR website! Solve:
You're on the right track! Subtract 49 from both sides. Take the square root of both sides. or Divide both sides by 5. or which can also be expressed as: or where:
There are no real solutions.