SOLUTION: Solve and Check 3[x-(2-x)-2x]=3(4-x). Im getting confused on what operation to start on first. If you can please help me and explain the problem i would really appreciate it.

Algebra ->  Equations -> SOLUTION: Solve and Check 3[x-(2-x)-2x]=3(4-x). Im getting confused on what operation to start on first. If you can please help me and explain the problem i would really appreciate it.      Log On


   

Question 210891This question is from textbook
: Solve and Check
3[x-(2-x)-2x]=3(4-x).
Im getting confused on what operation to start on first. If you can please help me and explain the problem i would really appreciate it. Thank you! This question is from textbook

Found 2 solutions by rfer, jim_thompson5910:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
3(x-(2-x)-2x)=3(4-x)
3(x-2+x-2x)=12-3x
3x-6+3x-6x=12-3x
+3x+3x-6x-6=12-3x
-6=12-3x
-18=-3x
multiply through by -
18=3x
6=x

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
3[x-(2-x)-2x]=3(4-x) ... Start with the given equation.


3x-3%282-x%29-6x=3%284-x%29 Distribute


3x-6%2B3x-6x=12-3x Distribute again.


-6=12-3x Combine like terms on the left side.


-6-12=-3x Subtract 12 from both sides.


-18=-3x Combine like terms.


-18%2F%28-3%29=x Divide both sides by -3 to isolate 'x'.


6=x Reduce


x=6 Rearrange the equation


----------------------------------------------------------------------

Answer:

So the solution is x=6





Check:

3[x-(2-x)-2x]=3(4-x) ... Start with the given equation.


3[6-(2-6)-2*6]=3(4-6) ... Plug in x=6 (ie replace each 'x' with 6)


3[6-(2-6)-12]=3(4-6) ... Multiply


3[6-(-4)-12]=3(-2) ... Combine like terms.


3[6+4-12]=3(-2) ... Rewrite -(-4) as +4


3[-2]=3(-2) ... Combine like terms.


-6=-6 ... Multiply


Since the equation is true, this verifies the solution x=6