SOLUTION: The sum of three consecutive integers are arranged such that twice the middle integer is equal to 9 more than the largest. What is the sum of the three integers?
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Question 139871: The sum of three consecutive integers are arranged such that twice the middle integer is equal to 9 more than the largest. What is the sum of the three integers? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Three consecutive integers, x, (x+1), (x+2)
:
The sum of three consecutive integers are arranged such that twice the middle integer is equal to 9 more than the largest.
2(x+1) = (x+ 2) + 9
:
2x + 2 = x + 11
:
2x - x = 11 - 2
;
x = 9 is the 1st integer
:
What is the sum of the three integers?
9 + 10 + 11 = 30
:
:
Check solution in the statement:
"twice the middle integer is equal to 9 more than the largest."
2 * 10 = 11 + 9
