SOLUTION: A stone is dropped into a mine shaft and hits the bottom 4.25 s later. How deep is the mine shaft? The equation for the distance an object falls in T seconds is T =sqrt(d/16), wher

Algebra ->  Equations -> SOLUTION: A stone is dropped into a mine shaft and hits the bottom 4.25 s later. How deep is the mine shaft? The equation for the distance an object falls in T seconds is T =sqrt(d/16), wher      Log On

From the condition, you write this equation


    4.25 = 


Then you square both sides


    4.25^2 = d/16


and finally obtain  d = 16*4.25^2 = 289 ft.    ANSWER