SOLUTION: I am a number with the digits 0,1,2. I am an even number. The numbers 2,3,and 6 are factors. The numbers 5 and 10 are not factors. Who am I?

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: I am a number with the digits 0,1,2. I am an even number. The numbers 2,3,and 6 are factors. The numbers 5 and 10 are not factors. Who am I?       Log On


   



Question 663235: I am a number with the digits 0,1,2. I am an even number. The numbers 2,3,and 6 are factors. The numbers 5 and 10 are not factors. Who am I?

Found 2 solutions by killer6678, MathTherapy:
Answer by killer6678(69) About Me  (Show Source):
You can put this solution on YOUR website!
The answer is impossible - a trick question.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
I am a number with the digits 0,1,2. I am an even number. The numbers 2,3,and 6 are factors. The numbers 5 and 10 are not factors. Who am I?

Since this number contains the digits, 0, 1, and 2, and is even, then it MUST be 102, 120, or 210

All three numbers have 2,3, and 6 as their factors. However, the third clue disqualifies 120 and 210, as that clue states that 5 and 10 are NOT factors of the number, and 120 and 210 both have 5 and 10 as their factors, while 102 DOES NOT.

Number is: highlight_green%28102%29

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