SOLUTION: Ming has 15 quarters, 30 dimes and 48 nickels. He wants to gruop his money so that each group has the same number of each coin, How much will each group be worth?

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: Ming has 15 quarters, 30 dimes and 48 nickels. He wants to gruop his money so that each group has the same number of each coin, How much will each group be worth?      Log On


   



Question 457563: Ming has 15 quarters, 30 dimes and 48 nickels. He wants to gruop his money so that each group has the same number of each coin, How much will each group be worth?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The greatest common divisor is 3, so
there are 3 groups. Each group will have the same number of
quarters, +15%2F3+=+5+
dimes, +30%2F3+=+10+
nickels, +48%2F3+=+16+
Each group has a value of:
+5%2A25+%2B+10%2A10+%2B+16%2A5+=+125+%2B+100+%2B+80+
+125+%2B+100+%2B+80+=+305+
Each group is worth $3.05
check answer:
+15%2A25+%2B+30%2A10+%2B+48%2A5+=+375+%2B+300+%2B+240+
+375+%2B+300+%2B+240+=++915+
and
+3%2A305+=+915+
OK