SOLUTION: If given the equation: {{{h=(-16t^2)+560t}}}, when does h become 0?

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Question 52249: If given the equation: h=%28-16t%5E2%29%2B560t, when does h become 0?
Answer by rchill(405) About Me  (Show Source):
You can put this solution on YOUR website!
Substitute 0 in for h and solve: 0=%28-16t%5E2%29%2B560t. Now factor that into 0=-16t%28t-35%29. That means that either -16t=0 or t-35=0, as either factor can be 0. Solving for each shows us that for the first equation that t=0, and for the second t=35.