SOLUTION: solve: 2y(y+4)=-5(y+3) 2y(y+4)-5(y+3)=0 unclear as to where to take it from there. I don't see how they got -3/2,5 out of that. I'm trying though.

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: solve: 2y(y+4)=-5(y+3) 2y(y+4)-5(y+3)=0 unclear as to where to take it from there. I don't see how they got -3/2,5 out of that. I'm trying though.      Log On


   

Question 47017: solve:
2y(y+4)=-5(y+3)
2y(y+4)-5(y+3)=0
unclear as to where to take it from there.
I don't see how they got -3/2,5 out of that. I'm trying though.
Answer by uuuu(3) About Me  (Show Source):
You can put this solution on YOUR website!
use the quadratic formula for the problem 2y^2+3y-15=0
I might be a little off since im doing this in my head but you should get close to or exactly y=-3/4-1/4 square root of 129 and y=-3/4+1/4 square root of 129 if you need to see the steps if youre still not getting it email me back