SOLUTION: Im very sorry i made a error on my last question the real question is how do you get k in this equation 6(k+2)+2(2k-5)=22

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: Im very sorry i made a error on my last question the real question is how do you get k in this equation 6(k+2)+2(2k-5)=22      Log On


   

Question 154949: Im very sorry i made a error on my last question the real question is how do you get k in this equation 6(k+2)+2(2k-5)=22
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
6(k+2)+2(2k-5)=22
then
6k+12+4k-10=22
then
10k+2=22
10k=20
k=2