You can put this solution on YOUR website! How do I wrtie an equation that will be perpendicular to 3x-5y=10 and passes through (-6,2)?
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slope of the given line is 3/5
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Therefore slope of the perpendicular line is -5/3
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Find the y-intercept if y = mx+b:
2 = (-5/3)(-6) + b
2 = 10 + b
b = -8
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Equation of the line:
y = (-5/3)x - 8
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Cheers,
stan H.
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