SOLUTION: Find x so that (x + 4,x) is equidistant from (0,5) and (8, -1)

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Question 1123421: Find x so that (x + 4,x) is equidistant from (0,5) and (8, -1)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!

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Similar problem.
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If the point (x,3) is equidistant from (3,-2) and (7,4). find x
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Find the equation of the line thru the 2 points given.
Find the equation of the perpendicular bisector of that line.
Sub 3 for y in that equation.
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Or:
d+=+sqrt%28%28x-3%29%5E2+%2B+5%5E2%29+=+sqrt%28%28x-7%29%5E2+%2B+1%29
%28x-3%29%5E2+%2B+5%5E2+=+%28x-7%29%5E2+%2B+1
x%5E2+-+6x+%2B+34+=+x%5E2+-+14x+%2B+50
-6x+%2B+34+=+-14x+%2B+50
8x = 16
x = 2