SOLUTION: The coordinate of a particle in meters is given by x(t) = 16t − 3.0t 3, where the time t is in seconds. The particle is momentarily at rest at t =

Algebra ->  Coordinate-system -> SOLUTION: The coordinate of a particle in meters is given by x(t) = 16t − 3.0t 3, where the time t is in seconds. The particle is momentarily at rest at t =      Log On


   

Question 1120392: The coordinate of a particle in meters is given by x(t) = 16t − 3.0t
3, where the time t is in
seconds. The particle is momentarily at rest at t =
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The coordinate of a particle in meters is given by x(t) = 16t − 3.0t
3, where the time t is in
seconds.
----------
x(t) = 16t - 3t = 13t
------
dx/dt = 13
---
The particle is momentarily at rest at t =
It's always at rest.

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
If the formula is  x(t) = 16*t - 3*t^2,  then the answer is 


x'(t) = 16 - 6t  =====>  x'(t) = 0 when  16-6t = 0  ====>  t = 16%2F6 = 8%2F3 seconds.

----------------

I'd say that the post is written in an unreadable way.

I need to guess what is written there . . .


It is not the method to prepare the posts to this forum.