SOLUTION: Polar representation of z= cos a-isina Where 0<a<2π
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Question 984931
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Polar representation of z= cos a-isina
Where 0
Answer by
ikleyn(53763)
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z = cos(a) -i*sin(a) = cos(-a) + i*sin(-a).
The modulus is 1.
The argument (the polar angle) is -a.