SOLUTION: Q.The variables x and y are related by the differential equation
(x2 + 4)dy/dx = 6xy.
It is given that y = 32 when x = 0. Find an expression for y in terms of x.
The answer is
Question 749772: Q.The variables x and y are related by the differential equation
(x2 + 4)dy/dx = 6xy.
It is given that y = 32 when x = 0. Find an expression for y in terms of x.
The answer is supposed to be: y=0.5(x^2+4)
but i get a different answer... please help soon exam is one day away!#Desperate
Thank you. Answer by blueplanet(7) (Show Source):
Replacing with , we get:
------- (3)
Integrating both sides of the equation, we get:
= -------- (4)
This expression can be simplified into:
I think this is the solution to the problem. I have checked the solution by differentiating it with respect to x. The end result is exactly the same as the equation given in the question:
Replacing with , we get:
Rearranging the equation, we get an equation exactly exactly the same as the equation given in the original question: