You can put this solution on YOUR website! Recall that vertex form is y=(x-h)^2 + k. Where (h,k) is your vertex.
Also recall that given standard form Ax^2 - Bx + C, the vertex is (-B/2A, f(-B/2A)).
Well x^2-4x-4 is pretty standard. Thus the x-coordinate of the vertex is -(-4)/2.
OR 4/2 ... which is 2.
now what is f(2)? 2^2 - 8 - 4 = -8... So our y-coordinate is -8.
The vertex is (2,-8) OR h=2 and k=-8.
So to put this in vertex form, we simply substitute.
for y=(x-h)^2 + k and h=2 k =-8 we get:
Hope this helped!
