SOLUTION: In Algebra 2, I have i raised to the 32nd. i is = to -1 so the answer would be one. Is this correct? Thanks Taylor

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Question 305001: In Algebra 2, I have i raised to the 32nd. i is = to -1 so the answer would be one. Is this correct?
Thanks
Taylor
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In Algebra 2, I have i raised to the 32nd. i is = to -1 so the answer would be one. Is this correct?
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Powers of "i":
i
i^2 = -1
i^3 = -i
i^4 = 1
----
i^(32) = [(i^)4]^8 = 1^8 = 1
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Cheers,
Stan H.
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