SOLUTION: (9-6i)^2
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Question 24684
:
(9-6i)^2
Answer by
algebrapro18(249)
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(9-6i)(9-6i)
you have to F.O.I.L. this:
First 9*9
Outer 9 * -6i
Inner 9 * -6i
Last -6i * -6i
combining this into 1 equation and simplifying
(81-54i-54i+36i^2)
81-108i+36i^2
Note: i^2 = -1
81-108i-36
45-108i