SOLUTION: y plus 3=8 3=a plus 7=a plus 7 6=x-4 7b=35 25=5y 10x=110 I need to know how to help my son begin and solve these questions. Its been a very long time since I have seen these

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: y plus 3=8 3=a plus 7=a plus 7 6=x-4 7b=35 25=5y 10x=110 I need to know how to help my son begin and solve these questions. Its been a very long time since I have seen these      Log On


   



Question 23965: y plus 3=8
3=a plus 7=a plus 7
6=x-4
7b=35
25=5y
10x=110
I need to know how to help my son begin and solve these questions. Its been a very long time since I have seen these.

Found 2 solutions by smallfry, elima:
Answer by smallfry(7) About Me  (Show Source):
You can put this solution on YOUR website!
this is how you start.............
y plus 3 =8
y+3=8, you want y or x whatever letter alone...so get rid of the 3
y+3=8
-3 -3
y=5, thats your answer.... make sure you plug in your answer to see if it works


if you need more help let me know.... applesauce_10@hotmail.com.....

Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
y + 3=8
3=a + 7
6=x-4
7b=35
25=5y
10x=110
I think the first 2 problems you wrote wrong. I hope I wasright in my assumption.
If so, here is how you solve them;
In each ofthe problems the object is to get the variable by itself "x,y, and a";
y+3=8
subtract 3 from both sides;
1)y+3-3=8-3
y=5
2)3=a+7
subtract 7 from both sides;
3-7=a+7-7
-4=a
3)6=x-4
add 4 to both sides;
6+4=x-4+4
10=x
4)7b=35
divide each side by 7;
7b%2F7=35%2F7
b=5
5)25=5y
divide each side by 5;
25%2F5=5y%2F5
5=y
6)10x=110
divide each side by 10;
10x%2F10=110%2F10
x=11
Hope you understand. If not let me know
=)