Question 1191126: In what bases b, does (b+8) divide into (7b+8) with no remainder
Found 2 solutions by Edwin McCravy, greenestamps: Answer by Edwin McCravy(20060) (Show Source):
You can put this solution on YOUR website!
Whether an integer divides into another integer with zero remainder has
nothing to do with what number base the integer is expressed in, so it's
as true in base ten as any other.
7
b+8) 7b+ 8
7b+56
-48
This will only be a positive integer if is a positive
integer.
The divisors of 48 are 1,2,4,6,8,12,16,24,48
b+8 = 1, 2, 4, 6,8,12,16,24,48
b = -7,-6,-4,-2,0, 4, 8,16,40
The only valid values of b which can be number bases are the positive
ones: 4, 8, 16, and 40.
Edwin
Answer by greenestamps(13200) (Show Source):
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