SOLUTION: solve the following equation for real numbers x and y. ((1+i)/(1-i))^2+1/(x+iy)=1+i.

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Question 1095684: solve the following equation for real numbers x and y.
((1+i)/(1-i))^2+1/(x+iy)=1+i.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
solve the following equation for real numbers x and y.
%28%281%2Bi%29%2F%281-i%29%29%5E2+%2B+1%2F%28x%2Biy%29+=+1%2Bi
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%28%281%2Bi%29%2F%281-i%29%29%5E2+=+%281%2Bi%29%5E2%2F%281-i%29%5E2+=+%282i%2F-2i%29+=+-1
--> -1+%2B+1%2F%28x%2Biy%29+=+1%2Bi
1%2F%28x%2Biy%29+=+2%2Bi
Invert
x%2Biy+=+1%2F%282%2Bi%29+=+%282-i%29%2F5
x = 2/5, y = -1/5