SOLUTION: Having issues with this problem, can you help? The sum of two numbers is 112. The second is 7 more than 4 times the first. What are the two numbers?

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Question 94409: Having issues with this problem, can you help?

The sum of two numbers is 112. The second is 7 more than 4 times the first. What are the two numbers?
Answer by praseenakos@yahoo.com(507) (Show Source):
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Question:
The sum of two numbers is 112. The second is 7 more than 4 times the first. What are the two numbers?
Answer:

Assume that the first number = x

Four times the first number = 4x

7 more than four times the first = 4x + 7

Given that The second is 7 more than 4 times the first.....

So the second number = 4x + 7

Their sum is given as 112

so we can write,

x + 4x + 7 = 112

==> 5x + 7 = 112

Subtract 7 from both sides...

5x + 7 - 7 = 112 - 7

==> 5x = 105

Divide both sides by 5

==>

==> x = 21

So the first number is 21

Then the second number is 4x + 7 = 4 * 21 + 7 = 84 + 7 = 91

So the numbers are 91 and 21.

Hope you found the explanation useful.

Regards.

Praseena.