SOLUTION: Write each of the equations below in standard form 1. y = 3(x–7)(x+4) 2.y = –2(x+3)(x+5)

Algebra ->  Average -> SOLUTION: Write each of the equations below in standard form 1. y = 3(x–7)(x+4) 2.y = –2(x+3)(x+5)      Log On


   

Question 890102: Write each of the equations below in standard form
1. y = 3(x–7)(x+4)
2.y = –2(x+3)(x+5)
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
I will do just number 1. You can then understand the process and do number 2 yourself.

y=3%28x%5E2-3x-28%29 multiplied the binomials but not the separate 3 factor.
The term which completes the square is %283%2F2%29%5E2.
y=3%28x%5E2-3x%2B%283%2F2%29%5E2-%283%2F2%29%5E2-28%29--add and subtract the square term inside parentheses
y=3%28%28x-3%2F2%29%5E2-9%2F4-28%29---factorize the square trinomial part
3%28%28x-3%2F2%29%5E2-9%2F4-112%2F4%29
3%28%28x-3%2F2%29%5E2-116%2F4%29
3%28%28x-3%2F2%29%5E2-29%29
y=3%28x-3%2F2%29%5E2-3%2A29
highlight%28y=3%28x-3%2F2%29%5E2-87%29



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See a separate lesson on Completing The Square.

Answer by MathTherapy(10553) About Me  (Show Source):
You can put this solution on YOUR website!

Write each of the equations below in standard form
1. y = 3(x–7)(x+4)
2.y = –2(x+3)(x+5)


y = 3(x - 7)(x + 4)

y+=+3%28x%5E2+-+3x+-+28%29

Standard form of a parabolic equation: highlight_green%28highlight_green%28y+=+3x%5E2+-+9x+-+84%29%29

You should be able to do the other!!