SOLUTION: Provided: m1v1 = m2v2, where m1 and v1 are the initial mass and velocity, respectively, and m2 and v2 are the final mass and velocity. A 21,000 pound train engine is tra

Algebra ->  Average -> SOLUTION: Provided: m1v1 = m2v2, where m1 and v1 are the initial mass and velocity, respectively, and m2 and v2 are the final mass and velocity. A 21,000 pound train engine is tra      Log On


   



Question 874747: Provided: m1v1 = m2v2, where m1 and v1 are the initial mass and velocity,
respectively, and m2 and v2 are the final mass and velocity.
A 21,000 pound train engine is traveling an average speed of
60 mi/hr. It strikes a stationary box car that weights 29,000
pounds. The train engine and box car continue mangled together
at what speed along the track?

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
m1v1 = m2v2,
21000 * 60 = (21000+29000)v2
126000 = 50000 * v2
v2 = 126000 / 50000 = 2.52 mph