SOLUTION: The average of seven different positive integers is 7 . what is the largest possible value of any of these numbers ?
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Question 322026: The average of seven different positive integers is 7 . what is the largest possible value of any of these numbers ? Found 2 solutions by Jk22, nyc_function:Answer by Jk22(389) (Show Source):
You can put this solution on YOUR website! Ans : 28
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a1+...+a7=7*7=49
we take a1 upto a6 as small as possible : a1=1, a2=2, ...a6=6
hence : a7=49-6*7/2=49-21=28
You can put this solution on YOUR website! You want the other six numbers to be as small as possible. The smallest the first six might be is 1,2,3,4,5,6 and the sum of these is 21. The total of all the numbers is 7x7=49 so the largest number would be 49-21=28.
