SOLUTION: If one angle is 3 times the measure of angle 2, and the third angle is 5 times the measure of angle 2 subtracted by 90, then find the measure of all three angles. I have been s

Algebra ->  Angles -> SOLUTION: If one angle is 3 times the measure of angle 2, and the third angle is 5 times the measure of angle 2 subtracted by 90, then find the measure of all three angles. I have been s      Log On


   



Question 898334: If one angle is 3 times the measure of angle 2, and the third angle is 5 times the measure of angle 2 subtracted by 90, then find the measure of all three angles.
I have been stumped on this problem for ever. I know they all equal 180, but i can't find the measure of angle 2 and when I do when i plug in the formula it ends up being more than 180.
Please help.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +alpha+ = angle 2
+3%2Aalpha+ = angle 1
+5%2Aalpha+-+90+ = angle 3
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Do you mean the 3 angles add up to 180 degrees?
If so,
+alpha+%2B+3%2Aalpha+%2B+5%2Aalpha+-+90+=+180+
+9%2Aalpha+-+90+=+180+
+9%2Aalpha+=+270+
+alpha+=+30+
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Angle 2 = 30 degrees
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Angle 1 = +3%2A30+
Angle 1 = 90 degrees
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Angle 3 = +5%2A30+-+90+
Angle 3 = +150+-+90+
Angle 3 = 60 degrees
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check:
+30+%2B+90+%2B+60+=+180+ degrees
OK