SOLUTION: two angels are suplementary, if the larger angle is 15º more than twice the smallest angle, find the neasure of both angles.

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Question 156018: two angels are suplementary, if the larger angle is 15º more than twice the smallest angle, find the neasure of both angles.
Answer by Electrified_Levi(103) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, Hope I can help,
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two angles are supplementary, if the larger angle is more than twice the smaller angle, find the measure of both angles.
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All Supplementary angles add up to 180º
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First, we have to assign variables to both angles
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We can use "x" as one angle, the smaller angle,
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If the larger is 15º more than twice the smaller angle(x)
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This is how you write the larger angle = +2%28smaller-angle%29+%2B+15+(smaller angle = "x") = +2%28x%29+%2B+15+ = +2x+%2B+15+
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Smaller angle = "x"
Larger angle = "2x + 15"
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Since these angles add up to be 180º we need to add the two angles together
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+%28x%29+%2B+%28+2x+%2B+15+%29+=+180+
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Now just solve for "x", we will get rid of the parentheses
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+x+%2B+2x+%2B+15++=+180+
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We will add like terms
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+x+%2B+2x+%2B+15++=+180+ = +3x+%2B+15++=+180+
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we will move "15" to the right side
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+3x+%2B+15+-+15++=+180+-+15+ = +3x+=+165+
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We will now divide each side by "3" to get "x"(our smaller angle)
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+3x%2F3+=+165%2F3+ = +x+=+55+
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"x" = 55
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Smaller angle = "x", or 55º
Larger angle = "2x + 15", (replace "x" with 55),+2%2855%29+%2B+15+ = +110+%2B+15+ = +125+, Larger angle = 125º
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We can check by replacing "x" with 55 in our equation
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+%28x%29+%2B+%28+2x+%2B+15+%29+=+180+ = +%2855%29+%2B+%28+2%2855%29+%2B+15+%29+=+180+
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+%2855%29+%2B+%28+2%2855%29+%2B+15+%29+=+180+ = +%2855%29+%2B+%28+110+%2B+15+%29+=+180+
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+%2855%29+%2B+%28+110+%2B+15+%29+=+180+ = +%2855%29+%2B+%28+125+%29+=+180+
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+%2855%29+%2B+%28+125+%29+=+180+ = +180+=+180+ ( True)
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Smaller angle = 55º
Larger angle = 125º
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Hope I helped, Levi