SOLUTION: an angle measures 43 less than six times the measure of its complement. Find the messure of both angles. I just need to know how to set these up I tried and got 6x-43=90 but i coul
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Question 154580: an angle measures 43 less than six times the measure of its complement. Find the messure of both angles. I just need to know how to set these up I tried and got 6x-43=90 but i couldnt figure out the "43 less than" part Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Let the angle you are tryng to find = A.
The complement of angle A = (90-A) and 6 times this complement is 6(90-A) and 43 less than that is 6(90-A)-43, so you can write:
A = 6(90-A)-43 Simplify and solve for A.
A = 540-6A-43
A = 497-6A Add 6A to both sides.
7A = 497 Divide both sides by 7.
A = 71 degrees
The complement of A = 90-A = 09-71 = 19 degrees.
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