SOLUTION: 2. The total of ages of X, Y and Z is 27. X is 2 years older than Y who happens to be twice as old as Z. What is the age of Y?

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Question 985181: 2. The total of ages of X, Y and Z is 27. X is 2 years older than Y who happens to be twice as old as Z. What is the age of Y?
Answer by MathLover1(20850) About Me  (Show Source):
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2.
if the total of ages of X, Y+and Z is 27, then we have

X%2BY+%2B+Z+=27
if X is 2+years older than Y, then
X=Y%2B2
if Y happens to be twice as old as Z, then
Y=2Z=>Z=Y%2F2
substitute Y%2B2 for X and Y%2F2 for Z
Y%2B2%2BY+%2B+Y%2F2+=27
2Y%2F2%2B2Y%2F2+%2B+Y%2F2+=27-2
5Y%2F2+=25
5Y+=25%2A2
5Y+=50
Y+=50%2F5
highlight%28Y+=10%29
now we can find X and Z
X=Y%2B2 =>X=12
Z=Y%2F2=>Z=5
check:
X%2BY+%2B+Z+=27
12%2B10+%2B+5+=27
27+=27