SOLUTION: present age of father is 5 more than 4 times the age of his son. if sum of their present ages is 45 .find the difference between their ages

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Question 985023: present age of father is 5 more than 4 times the age of his son. if sum of their present ages is 45 .find the difference between their ages
Answer by macston(5194) About Me  (Show Source):
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.
F=age of father; S=age of son
F=4S+5
.
F+S=45
(4S+5)+S=45
5S=40
S=8 The son is 8 years old.
F=4S+5=4(8)+5=32+5=37 The father is 37 years old.
F-S=37-8=29 ANSWER: The difference in their ages is 29 years.