Question 895466: A woman is 3 times as old as her son . 8 years ago the product of their child was 112. Find thier present age.
Please help me out. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A woman is 3 times as old as her son . 8 years ago the product of their ages was 112. Find thier present age.
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Equations:
w = 3s
(w-8)(s-8) = 112
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Substitute for "w" and solve for "s"::
(3s-8)(s-8) = 112
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3s^2 - 24s - 8s + 64 = 112
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3s^2 - 32s - 48 = 0
Factor::
(s-12)(3s+4) = 0
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Positive solution::
s = 12 yrs (the son's age now)
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Solve for "w"::
w = 3s
w = 36 yrs (the woman's age now)
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Cheers,
Stan H.
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