SOLUTION: Two years ago a father was four times as old as his son. Three years from now the father will be only three times as old as the son. How old is each now?
{son is yrs., father is
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{son is yrs., father is
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Question 78589: Two years ago a father was four times as old as his son. Three years from now the father will be only three times as old as the son. How old is each now?
{son is yrs., father is yrs.}
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Let x=son's age now
Then x-2=son's age two years ago
And 4(x-2)=father's age two years ago
So 4(x-2)+2=4x-8+2=4x-6=father's age now
Also x+3=son's age three years for now
And 3(x+3)=father's age three years from now
Now if we subtract 5 years from father's age three years from now, then that will equal father's age two years ago. So:
3(x+3)-5=4(x-2) get rid of parens
3x+9-5=4x-8
3x+4=4x-8 subtract 4 and also 4x from both sides
3x-4x+4-4=4x-4x-8-4 collect like terms
-x=-12 divide both sides by -1
x=12-----------------------------------son's age now
4x-6=4*12-6=48-6=42-------------------------father's age now
CK
Two years ago, father was 4 time as old as his son:
4(12-2)=42-2
40=40
also
Three years from now father will only be three times as old as his son
3(12+3)=42+3
45=45
