SOLUTION: The sum of the digits of a two digit number is 9. If the digits are reversed, the number formed bears the ratio 3:8 to the original number. Find the original number (Ans. 77)

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Question 567574: The sum of the digits of a two digit number is 9. If the digits are reversed, the number formed bears the ratio 3:8 to the original number. Find the original number (Ans. 77)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
let the tens digit = +a+
Let the units digit = +b+
The actual number is +10a+%2B+b+
The number with the digits reversed is +10b+%2B+a+
given:
(1) +a+%2B+b+=+9+
(2) +%28+10b+%2B+a+%29+%2F+%28+10a+%2B+b+%29+=+3%2F8+
------------
Multiply both sides of (2) by +8%2A%28+10a+%2B+b+%29+
(2) +8%2A%2810b+%2B+a%29+=+3%2A%28+10a+%2B+b+%29+
(2) +80b+%2B+8a+=+30a+%2B+3b+
(2) +22a+-+77b+=+0+
(2) +22a+=+77b+
(2) +a+=+%2877%2F22%29%2Ab+
(2) +a+=+%287%2F2%29%2Ab+
Substitute (2) into (1)
(1) +%287%2F2%29%2Ab+%2B+b+=+9+
(1) +7b+%2B+2b+=+18+
(1) +9b+=+18+
(1) +b+=+2+
and, since
(1) +a%2B+b+=+9+
(1) +a+%2B+2+=+9+
(1) +a+=+7+
The original number is 72
check answer:
(2) +%28+10b+%2B+a+%29+%2F+%28+10a+%2B+b+%29+=+3%2F8+
(2) +%28+10%2A2+%2B+7+%29+%2F+%28+10%2A7+%2B+2+%29+=+3%2F8+
(2) +27+%2F+72+=+3%2F8+
Multiply both sides by +72+
(2) +27+=+3%2A9+
(2) +27+=+27+
OK
Note that the answer +77+ is impossible,
since the digits have to add up to 9