SOLUTION: The ancient one is 40 years older than the youngster. 10 years agos, the age of the ancient one was 22 years greater than seven times the age of youngster then. How old are both of
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Question 521502: The ancient one is 40 years older than the youngster. 10 years agos, the age of the ancient one was 22 years greater than seven times the age of youngster then. How old are both of them today? Found 3 solutions by stanbon, Maths68, MathTherapy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The ancient one is 40 years older than the youngster. 10 years agos, the age of the ancient one was 22 years greater than seven times the age of youngster then. How old are both of them today?
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Equations:
a = y + 40
(a-10) = 5y+22
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Substitute for "a" and solve for "y":
(y+40-10) = 5y+22
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y + 30 = 5y + 22
4y = 8
y = 2 yrs old (the younster's age now)
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Solve for "a":
a = y + 40
a = 2+40 = 42 yrs old (the ancient's age now)
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Cheers,
Stan H.
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The ancient one is 40 years older than the youngster
a=b+40..........(1)
10 years ago,
age of ancient one was = a-10
age of youngste was = b-10
Then,the age of the ancient one was 22 years greater than seven times the age of youngster
a-10=7(b-10)+22
a-10=7b-70+22
a=7b-70+22+10
a=7b-70+32
a=7b-38..........(2)
Put the value of a from (1) to (2)
b+40=7b-38
b-7b=-38-40
-6b=-78
-6b/-6=-78/-6
b=-78/-6
b=13
put the value of b (1)
a=b+40
a=13 + 40
a=53
Present age of ancient DISABLED_event_one= a = 53 years old
Present age of youngste = b = 13 years old
You can put this solution on YOUR website! The ancient one is 40 years older than the youngster. 10 years agos, the age of the ancient one was 22 years greater than seven times the age of youngster then. How old are both of them today?
Let ancient's age be A, and youngster's, Y
Then, A = Y + 40 -------- eq (i)
A – 10 = 7(Y – 10) + 22 ----- A – 7Y = - 38 -------- eq (ii)
Y + 40 – 7Y = - 38 ------- Substituting Y + 40 for A in eq (ii)
- 6Y = - 78
Y, or youngster = , or years-old
A = 13 + 40 ------ Substituting 13 for Y in eq (i)
A, or ancient's age =
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Check
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Ancient is 40 years older than youngster
53 = 40 + 13
53 = 53 (TRUE)
10 years ago, ancient was 22 years older than 7 times youngster's age then
53 - 10 = 7(13 - 10) + 22
43 = 7(3) + 22
43 = 21 + 22
43 = 43 (TRUE)
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