SOLUTION: 9 years ago a woman was 3 times as old as her son, in 8 years from now the sum of their ages = 78

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Question 1137964: 9 years ago a woman was 3 times as old as her son, in 8 years from now the sum of their ages = 78
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
today woman is x, son is y
x-9=3(y-9)
x-9=3y-27
3y-x=18
in 8 years x+8 and y+8 and that sum is 78, so x+y+16=78
x+y=62
x=62-y
so 3y-62+y=18
4y=80
y=20 son
x=42 mother
nine years earlier it was 33 and 11
8 years from now it will be 50 and 28