SOLUTION: A man has a daughter and a son. The son is three years older than the daughter. In one year the man will be six times as old as the daughter now. In ten years the man will be fourt

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Question 1086190: A man has a daughter and a son. The son is three years older than the daughter. In one year the man will be six times as old as the daughter now. In ten years the man will be fourteen years older than the combined ages of his children at that time. What is the man's present age?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
m, Man
d, Daughter
s, Son

system%28s=d%2B3%2Cm%2B1=6d%2Cm%2B10=%28d%2B10%29%2B%28s%2B10%29%2B14%29
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m%2B10=d%2Bs%2B34
m=d%2Bs%2B24
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m=%28m%2B1%29%2F6%2B%28d%2B3%29%2B24
m=%28m%2B1%29%2F6%2B%28m%2B1%29%2F6%2B27
m=2%28m%2B1%29%2F6%2B27
6m=2m%2B2%2B162
4m=164
highlight%28m=41%29