SOLUTION: In a family there are 3 brothers, each 2 years apart in age.
Their ages total 42.
Form an equation and solve it to find the age of each child.
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Their ages total 42.
Form an equation and solve it to find the age of each child.
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Question 1028382: In a family there are 3 brothers, each 2 years apart in age.
Their ages total 42.
Form an equation and solve it to find the age of each child.
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youngest brother's age be x
the brothers ages will be
x,(x+2), (x+2+2)
x+x+2+x+4=42
3x+6 =42
3x = 36
x=12
12,14,16 are their ages
