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Well, you know the formula for the area of a parellogram:
A = bh (Area = Base times the Height)
You know the base, 10. Draw the rhombus (any size will do, make it a convenient size). One of the bottom angles is 45 degrees, and the other is 135 degrees. Find the 45 degree angle (the acute, more closed angle). The base forms one side of that angle, and another side of the rhombus forms the other side of the angle. Where that other side of the rhombus goes up and touches the top of the rhombus, at that point draw an altitude down to the base. That will form a triangle, won't it? The Base, the other side of the 45 degree angle, and the altitude.
Now, you know the altitude forms a 90-degree angle with the base, right? So your triangle has an angle of 90, one of 45, and the one that is left must be 45, so they all total 180 degrees, as the angles in every triangle do.
So your triangle has two 45 degree angles. So it must be an isosceles triangle, right? It has two equal angles, and two equal sides, and the sides opposite those equal angles must be equal, right? So the two sides opposite those equal 45-degree angles are the altitude and the base. So the altitude and the base are equal, aren't they? And you already know the base is 10 feet. So the altitude must also be10 feet.
So the base is ten feet, and the altitude is 10 feet. A=bh. Can you take it from there?
Don't be afraid to go over this a few times until you see it clearly.

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Solve 2x = 30.
If this equation had asked me to "Solve 2x = 32", it would have been easy, because I could have converted the 32 to 25, set the exponents equal, and solved for "x = 5". But 30 is not a power of 2, so I can't set powers equal to each other. I need some other method of getting at the x, because I can't solve with the equation with the variable floating up there above the 2; I need it back down on the ground where it belongs. And I'll have to use logarithms to get at it.
When dealing with equations, I can do whatever I like to the equation, as long as I do the same thing to both sides. And, to solve an equation, I have to get the variable by itself on one side of the "equals" sign; to isolate the variable, I have to "undo" whatever has been done to it.
In this case, the variable x has been put in the exponent. The backwards (technically, the "inverse") of exponentials are logarithms, so I'll need to undo the exponent by taking the log of both sides of the equation. This is useful to me because of the log rule that says that exponents inside a log can be turned into multipliers in front of the log:
logb(mn) = n · logb(m)
When I take the log of both sides of an equation, I can use any log I like (base-10 log, base-2 log, natural log, etc), but some are sometimes more useful than others. Since the base in the equation "2x = 30" is "2", I might try log-base-2:
log2(2x) = log2(30)
xlog2(2) = log2(30)
x(1) = log2(30)
x = log2(30)
But I can't evaluate this in my calculator unless I apply the change-of-base formula:
x = log2(30)
= ln(30)/ln(2)
What would happen if I just used the natural log in the first place?
2x = 30
ln(2x) = ln(30)
xln(2) = ln(30)
x = ln(30)/ln(2)
Either way, I get the same answer, but taking natural log in the first place was simpler and shorter.

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3/2m=m+7
-m -m
.5m=7
7/.5=14
m=14

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7.95=159/20 and 7.99=799/100

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THERE IS 2 SOLUTION !!
3x-6=18 and 3x-6=-18
3x-6=18
+6 +6
3x=24
24/3=8
x=8
ok here 2nd solution
3x-6=-18
+6 +6
3x=-12
x=-4
so u will put ur answer as -4 and 8

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2x+3>13
-3 -13
2x>10
divide everything by 2
2x/2=x 10/2=5
x>5

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THERE IS 2 SOLUTION
3x-9=18 and 3x-9=-18
hope you know how to solve these 2
when u put the answer u have to put both solution

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2L+2W=66
LxW=216

so start with 2L+2W=66 lets solve for W
2L+2W=66
-2L -2L
2W=66-2L
divide everything by 2
2w/2=w 66/2=33 -2L/2=-L
so new equation is w=33-L ok lets start on the 2nd equation
LxW=216
replace W with (33-L)
Lx(33-L)=216
-L^2+33L=216
so L=9
ok lets find W now
2(9)+2W=66
2W=48
W=24
L=9
24x9=216

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y+7=8x
subtract 7
y+7=8x
-7 -7
y=8x-7
y=mx+b
slope=M
so 8 is the slope

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x=1/3 check if its right
3(1/3)^2+2(1/3)

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8y-x=48
subtract -x
postive - negative= postive 48-(-x)=x+48
8y=x+48
divide everything by 8
8y/8=y, x/8=(1/8)x, 48/8=6
so the new equation is
y=(1/8)x+6
y=mx+b
M=slope
so (1/8) is the slope

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25n^2=16
x=4/5 or .8 check it if its right
25(.8)^2

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3x^2=13x-14
x=2 and 1/3 check if its right 3(2+1/3)^2=13(2+1/3)-14

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3x+2 x=5
3(5)+2= 17

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x=5 divde by 35
x=5/35

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first number=x 2nd number= y
The sum of 2 numbers is 40
so x+y=40
x/y = 4+5/y
x = 4y+5
x+y=40
4y+5+y=40
5y+5=40
5y=35
y=7
x=4y+5=4(7)+5=28+5=33
Answers: numbers are 33 and 7

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8-12x=6(1+x)
8-12x=6+6x
-6x -6x
8-18x=6
-8 -8
-18x=-2
divide -2 by -18
-2/-18=2/18
=1/9

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make a graph go to your y-int wwhich is -2 so draw a point at (0,-2)
then go up 3 point go right 4 points because is 3/4

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isnt there suppose to be 2 equations?
LOL IF THERE IS 3 VERABLES THEN THERE WILL BE 3 EQUATION

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x/z=6/5
x=6 z=5 lawl
x+z/z=(6+5)/5
=11/5

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y=6x so just replace y with (6x)
so 6x=5x+7
don't tell me u can't solve 6x=5x+7

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N=3.5
check it if its right -10(3.5)^2+35(3.5)

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x=36

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6-2=4
6^2+2^2=40

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if you walk 5miles per hour
then it take 210 hours

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L=10
W=2
2(2)+2(10)=24
10-2=8

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A=LxW
A=1 1/2 X 2 3/4
A=33/6

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12 times

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60000-6000=54000
60000(.1)=x
.1=10%

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Type B : 50 pounds 50x5=250
Type A : 40 pounds 40x3=120
120+250=370$

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Y=3X+4 THE Y INTERCEPT(b)=(0,4)
NOW SET Y=0 & SOLVE FOR X
0=3X+4
3X=-4
X=-4/3 THUS THIS POINT IS (-4/3,0)
NOW PLOT THESE 2 POINTS & DRAW THE LINE THROUGH THEM WITH A SLOPE (m) OF 3.
[THIS IS THE RED LINE].

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Y=-3X-4 HAS A Y INTERCEPT OF (0,-4)
NOW SET Y=0 & SOLVE FOR X
0=-3X-4
-3X=4
X=4/-3 THUS THIS POINT IS (-4/3,0)
NOW PLOT THESE 2 POINTS AND DRAW A LINE THROUGH THEM WITH A SLOPE (m) OF -4/3
[THIS IS THE GREEN LINE]
(graph 300x200 pixels, x from -6 to 5, y from -10 to 10, of TWO functions y = 3x +4 and y = -3x -4).
Answer by rapaljer(4420) (Show Source):
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In contrast to the last problem that I posted about graphing straight lines, these two lines are given in SLOPE-INTERCEPT FORM (y=mx+b). In these cases, you can immediately identify the slope and the y-intercept of each line. The number term is always the y-intercept, and the coefficient of x is always the slope, which can be written as a fraction that we call the "RISE OVER THE RUN". Then you can graph them as follows:
y=3x-4
The y intercept is -4, and the slope m=3, which means .
Start by graphing the y-intercept by going DOWN 4 units on the y-axis. Then starting with your pencil on this point,GO UP 3 units, then go to the RIGHT 1 unit, and put the next point. Connect these two points with a line, and continue the line in both directions.


y=-3x-4
The y intercept is -4, and the slope m=-3, which means .

Start by graphing the y-intercept by going DOWN 4 units on the y-axis. Then starting with your pencil on this point,GO DOWN 3 units, then go to the RIGHT 1 unit, and put the next point. Connect these two points with a line, and continue the line in both directions.

If you want to see the point of intersection for these equations, then graph the two lines on the same graph, and see where the lines cross. This point is the point of intersection of the two lines.

For additional help on most AMU topic in algebra, see my website by clicking on my tutor name "rapaljer" anywhere in algebra.com. Look for the topic "Math in Living Color", choose a level of math, either Basic, Intermediate, or College Algebra, and look for the topic you need help with. If you can't find what you need, send me an Email, and maybe I can help you find the right page on my website!!!
R^2 at SCC