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No need to shout :)
Let x be his age now
Nine years ago he was
Five years hence, he will be
You are told




So check answer, is x+5 =(21) 3 times (x-9)=(7) ??

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I added a lot of intermediate steps so you could see the math

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Looks like this could be that missing person

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where x = 30, y =2 and z=-2

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the pole is 12 feet high. the angle of elevation at the end of the shadow to the top of the pole is 60,
How far is the tip of the shadow from the top of the pole?
You are looking at a 30:60:90 right triangle with the side opposite the 60 degree angle being 12 feet.
Sine is opposite/hypoteneuse
http://www.mathsisfun.com/sine-cosine-tangent.html


Just solve that and you go it

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So


The two distances are the same, so

You are also told . So



So SpeedLawanda is 45+15 = 60.
Check your answer
is 3*60 = 4*45??

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48. Which is 2 packs of plates and 3 packs of cups.
So what is that math behind that?
Find the prime factorization for each (24 and 16)
24 = 2*2*2*3
16 = 2*2*2*2
Now pick the factor from each that occur the most
there are 3 factors of 2 in 24; and 4 factors of 2 in 16. So use 4 factors of 2
24 has one factor of 3; 16 has none.l so use one factor of 3.
That is all the prime factors 24 and 16 have in them.
Now multiple the largest occurrences together

for this case, the answer was simple enough to see without doing all the math. But you need to know the math for the harder problems ahead.

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solve each inequality separately and then combine the result






combine

So x is between 1 and 9 but not equal to either 1 or 9

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Numerator is on the top. denominator is on the bottom.
Unless you are going to use division to get the number in decimal form, I would simply attempt to reduce the fraction by finding common factors and cancelling them out.
here is a handy URL for that.
http://www.mathwarehouse.com/arithmetic/numbers/prime-number/prime-factorization-calculator.php
In this case, 977 is prime, so it cannot be reduced.
You will need to resort to using long division to convert to decimal (or use a calculator). Divide the top number by the bottom one

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You need to find the various combinations that don't allow repetition. That means, the order of the people in the group doesn't matter.
Look at this URL http://www.mathsisfun.com/combinatorics/combinations-permutations.html
Scroll to the bottom and see the equation is given by
n!/(r!(n-r)!)
n is 10, r is 6. so plug in and solve
10! / (6! * 4!)

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Depends on where you live. But if where you live actually has a 20 cent coin that has a head on one side of it, then sure. If you live in the USA, there is no such thing as a 20 cent coin -- so it can't happen.

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is percent

%

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same side interior angles total 180




3x = 105
2x+5 = 75

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The volume of water the trough can hold is given by the volume of the 'box' formed by the sides of the trough.
That is
Also note that any volume has 'units' associated with it.




The term is pronounced as 'feet cubed' ... also known as cubic feet

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You are told y varies directly with x. So you can write the equation as whre A is a constant. You are then given two points. Use the first point to solve for A. Then use the information in the second point to solve for y. As follows
plug int he coordinates from the first point and solve for A



plug A into the base equation to get
now plug in the second value for x and solve for y

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get the result to one with only positive exponents. So 'move the a^-3 up to the numerator

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This is a very difficult question to answer. It would be simple to say "Robert needs to draw a 7 or less. An ace will be counted as a 1. There are 13 cards in a suit so 7/13 of them will suffice". But that is too simple. Robert has already been dealt enough cards to total 14. What you are not told is what cards are already played (both to Robert and to whatever other payers are in the game -- including the dealer) and how many cards are left to draw from. Without those two pieces of information, you can't give a definitive answer. And that is why card counting is so difficult.
Let's assume the simple answer and say 7/13's. That will be pretty close.

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subtract 29 from both sides. Add 6u to both sides
simplify
divide both sides by 11 to find u

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Factoring the difference of 2 squares is something you will need to be able to do. Those type of problems come up a lot
In general
is a difference of 2 squares. Where one term is 6y and the other is z



there you go
Often you will be given term that are higher order, for example

And you can see that first term is still a difference of 2 squares so it can be factored again. So keep your eye open for that

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You need to understand one of the properties of logs in order to do this
See this URL --> http://www.purplemath.com/modules/logrules.htm
Property 1 says logb(mn) = logb(m) + logb(n)
For your problem 1, you are asked for log b 21
That can be written as log b (2*11)
Which is log b 2 + log b 11
You are given the values for both terms, so just add them up.
Same idea for the other two problem
161 = 2 * 3 * 11 So use add those to get the result
2310 = 5 * 3 * 2 * 11 * 7
Since you are not given the log b 7, you can't solve this one with the info provided

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Circumference of a circle is given by where r is the radius. You are told you can use 3.14 for pi and that the radius is 11 inches
So

So plug in 11, solve for C. And then round to the nearest 10.
138.2 inches

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Use the Pythagorean theorem







You will notice that the sides are in a ratio of 15:20:25
Which is 3:4:5
Any triangle in ratio 3:4:5 is a right triangle.
That comes up a lot, so you might want to memorize that.

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Look at this URL
http://www.mathsisfun.com/geometry/interior-angles-polygons.html
Read it and see how one can build on what you know about triangles and extend that into the general rule.
In your specific case,

So simplify and solve for n

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let the number be represented by x
isolate the variable term by subtracting 7 from both sides
isolate the variable by dividing both sides by 2

the answer is 3/2 or 1.5

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post the problems here and if you want to get good help, do as much of them as you can and show your work.

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The rational zeros theorem (also called the rational root theorem) is used to check whether a polynomial has rational roots (zeros). It provides a list of all possible rational roots of the polynomial equation , where all coefficients are integers. If the equation has rational roots p/q, where p and q are integers, then p must divide evenly into the constant term a0 and q must divide evenly into the leading coefficient an. In other words, p is a factor of ±a0 and q is a factor of ±an.
http://www.chegg.com/homework-help/definitions/rational-zeros-theorem-27

get all the factors in the high order coefficient. Then get all the factors in the constant term
2 -- -2,-1,1,2
-6 -- -6,-3,-2,-1,1,2,3,6
now make every combination of the ratio of factors of -6 to factors of 2
-6/-2, -6/-1, -6/1, -6/2, -3/-2, .... 6/-2, 6/-1, 6/1, 6/2

now eliminate all the duplicates, and you are done.
Note this does not mean all these numbers ARE roots, it merely says that if there are roots, then these are the only possible ones.

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